exam calculus question

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ivpohv

Mathematics

Question Description

Find the maximum possible area of a rectangle that could fit in the space between the x-axis and the parabola -2x4 + 8.

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Explanation & Answer

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The area of the rectangle = 2X * Y.
Y = -2X^4+8
by substitution, then the rectangle
Area = 2X * - (-2X^4+8)

set the equation to 0

0 =  2X +2x^4+8

taking the derivative of the equation:

0 = 2+8x^3

x^3=-2/8

and solve for X;

x=(-2)^1/3/2


please clear the equation i am not understanding...............................

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ivpxl qnivq (178)
University of Virginia

Anonymous
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