Fe(s) + 2HCl(aq)FeCl2(s) + H2(g) H° = -7.4 kJ and S° = 107.9 J/K The maximum a

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Znpx12

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Question Description

Fe(s) + 2HCl(aq)FeCl2(s) + H2(g)


H° = -7.4 kJ and S° = 107.9 J/K

The maximum amount of work that could be done when 2.15 moles of Fe(s) react at 326 K, 1 atm is  kJ.

Assume that H° and S° are independent of temperature.

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Explanation & Answer

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H=-7.4kj

S=107.9j/k

no of moles =2.15of FE reacting to 326k

amount of work=326/107.9*-7.4/2.15=3.02 kj.

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Boston College

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