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Dividing both sides of the initial equation by 3x and multiplying both sides by dx gives the equation:

dy = (sqrt(x^2-25)/(3x))dx

This equation can be integrated leaving the equation:

y = (1/9)(sqrt(x^2-25)^(3/2)) + C.

Plugging in the point (5,3) means C = 3 so the final answer is:

y = (1/9)(sqrt(x^2-25)^(3/2)) + 3

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