Write a tangent function, h(x), such that the halfway points on one period are (-pi/2, -2) and (pi/2, 4).

Thank you for the opportunity to help you with your question!

where B = (the natural period of tan)/(period of this function), D is the phase shift and C is the vertical shift, we want an equation where

b=pi/(-pi/2)+pi/(pi/2)

b=4pi

so we have 2 y so we have 2 vertical shifts so we have to make 2 functions

h(x)=tan(4pi(x)-2

h(X)=tan(4pi(x)+4)

Thank you. Would you please clarify how you found b = 4pi from b=pi/(-pi/2)+pi/(pi/2)? I get b = 0...

Secure Information

Content will be erased after question is completed.

Enter the email address associated with your account, and we will email you a link to reset your password.

Forgot your password?

Sign Up