Conservation of Energy

Physics
Tutor: None Selected Time limit: 1 Day

Mr. Maloney's pendulum is swing back and forth. He has a 1 kg mass on the end, the string length is 2 meters, and he started it by pulling it back 35 degrees, determine:

a. The initial potential energy

b. Speed at the bottom

c. Speed half way to the bottom

d. How high would it go if a student have it a 3 m/s push

Jun 3rd, 2015

Thank you for the opportunity to help you with your question!

a. The initial potential energy can be determined by the expression mgh. Assuming the pendulum touches the ground at an angle of 0, the height is 0.264. This gives the potential energy of 2.64J.

b. The speed at the bottom can be solved by using the equation 2.64 = (1/2)mv^2. This gives a speed of 2.30m/s

c. The speed halfway to the bottom can be solved by using the equation (1/2)2.64 = (1/2)mv^2. This gives a speed of 1.62m/s

d. This increases the initial total energy by 4.5J so 2.64 + 4.5 = mgh. Solving for h gives a height of 0.714m

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jun 3rd, 2015

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
...
Jun 3rd, 2015
...
Jun 3rd, 2015
Dec 10th, 2016
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer