trigonometric substitution

label Calculus
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schedule 1 Day
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Jun 3rd, 2015

Thank you for the opportunity to help you with your question!

After integrating,

y = 1/3 (sqrt(-25+x^2)+5 tan^(-1)(5/sqrt(-25+x^2))) + C

so plugging in y(5) = 3

y = 1/6 (18-5 π+2 sqrt(-25+x^2)+10 tan^(-1)(5/sqrt(-25+x^2)))

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jun 3rd, 2015

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