I can't understand this assignment!! Statistic

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Ovane

Mathematics

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Probability Reasoning statistic homework I attached the file below. If anyone is willing to work on it for me that would me very helpful.

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MacBook Air 7. Your boss asked you to find a 95% confidence interval for the percent of college seniors who get their first choice of courses when registering for classes in the Fall semesters as compared to the number of freshman who get their first choice of courses. You found the resulting interval for average of seniors minus average of freshman to be (29.5%, 38.5%). Carefully interpret this confidence internal in the context of the problem. 8. We are going to develop a survey to determine the proportion of MTSU students who have obtained the flu shot. We want our 95% confidence interval to be within 3 percentage points. How many students do we need to survey? (In a prior survey, they found that 25% had obtained a flu shot.) 9/10/11. In a 1984 survey of licensed drivers in Wisconsin, 264 of 1140 women and 214 of 1200 men said that they did not drink alcohol. Conduct the appropriate test of significance to assess whether these sample data provide evidence that Wisconsin women abstain from drinking alcohol at a higher rate than Wisconsin men. Interpret the result in the context of the problem. (a - 05) Let group 1 be the women and group 2 be the men. Null Hypothesis: Alternative Hypothesis What test did you run Decision (reject/fail to reject Ho) Interpretation (in the context of the problem: p-value 12/13Resting pulse rates for a random sample of 26 smokers had a mean of 80 beats per minute (open) and a standard deviation of 5 bpm. Among 32 randomly chosen non-smokers, the mean and standard deviation were 74 and 6 bpm. Both sets of data were roughly symmetric. A hypothesis test found evidence of a difference in mean pulse rate between smokers and non-smokers at the a- .05 level of significance. Create a 95% confidence interval to estimate this difference. Let group 1 be the smokers and group 2 be the non-smokers. What interval did you use Confidence interval: Interpretation:
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Explanation & Answer

Attached.

7. Interpretation of confidence interval:
We are 95% confident that the true population parameter ‘percentage of seniors minus percentage of
freshman getting their first choice of courses’ is between 29.5% and 38.5%.

8.
From given data,
𝑝̂ = 0.25
𝑀𝑎𝑟𝑔𝑖𝑛 𝑜𝑓 𝐸𝑟𝑟𝑜𝑟(𝐸) = 0.03
For 95% confidence interval, 𝛼 = 0.05
For 𝛼 = 0.05, 𝑧𝛼 = 1.96
2

𝑧𝛼
Sample size (𝑛) = 𝑝̂ (1 − 𝑝̂ ) (

2

1.96 2
) = 800.33
) = 0.25 ∗ 0.75 ∗ (
𝐸
0.03
2

Round up 𝑛 to nearest integer, 𝑛 = 801
So, 801 students need to be surveyed from 95% confidence interval to be in 3% points.

9/10/11.
If proportion of woman and man abstaining from drinking alcohol are respectively 𝑝1 and 𝑝2 :
Null Hypothesis 𝑯𝟎 : 𝑝1 ≤ 𝑝2
Alternative Hypothesis 𝑯𝒂: 𝑝1 > 𝑝2
What test did you run: z-test
To calculate p-value:

𝑝
̂1 =

264
= 0.2316
1140

𝑝
̂2 =

214
= 0.1783
1200

We will use 𝑝1 − 𝑝2 = 0 (𝑎𝑠 𝑝𝑒𝑟 𝑎𝑠𝑠𝑚𝑒𝑑 𝑖𝑛 𝑛𝑢𝑙𝑙 ℎ𝑦𝑝𝑜𝑡ℎ𝑒𝑠𝑖...


Anonymous
This is great! Exactly what I wanted.

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