Write a tangent function, h(x), such that the halfway points on one period are (-pi/2, -2) and (pi/2, 4).
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the tangent function is tan(x+pi/2)-2
Hi Fatin. Would you please show your work - how you figured out the values of b, h, and k, etc.? Thank you.
ok, please wait for a moment, I'm in the middle of an exam, hope you don't mind :) thanks
assume y=a tan(b(x-h))+ka=amplitudeb=w (omega)h=horizontal shiftk=midline
thus we have y=3tan(0.5x-0.5h)+k, plug in the two points we get:
if you solve the system of equations, you will get h=pi/2, k=1
thus the equation is y=3 tan(1/2x-pi/4)+1
sorry I got the answer wrong the first time....please don't be mad....I didn't have enough time, sorry...
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