I'm doing a finals review and I don't remember this section.The instructions are: find all solutions of the equation in the interval [0, 2 π)

There are two problems:

4cos(^2)x - 3 = 0

csc(^2)x - cscx = 0

Thank you for the opportunity to help you with your question!

cosx = +-sqrt(3)/2,

x = pi/6, 11pi/6, 7pi/6, 5pi/6

cscx(csc(x-1)=0

no solution for csc =0,

cscx = 1 ---> sinx = 1

x = pi/2

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