Trigonometry math question


label Calculus
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Jun 4th, 2015

Thank you for the opportunity to help you with your question!

hi, I would love to answer your question, do you mind to type it out and post it again? Thank you

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jun 4th, 2015

Is better if you help me with this one,

(Sec x - csc x )/(sec x + csc x ) = (tan x-1/ tan x+1) 

Jun 4th, 2015

so you want me to prove it right? Also is it tan(x-1) or tanx-1?

Jun 4th, 2015

Tanx-1

Jun 4th, 2015

left side:

secx-cscx=1/cosx - 1/sinx=(sinx-cosx)/(cosx*sinx)

secx+cscx=(sinx+cosx)/(cosx*sinx)

so (Sec x - csc x )/(sec x + csc x ) =(sinx-cosx)/(sinx+cosx)

right side:

(tanx-1)/(tanx+1)=(sinx/cosx - 1)/(sinx/cosx +1)=(sinx-cosx)/cosx / (sinx+cosx)/cosx=(sinx-cosx)/(sinx+cosx)

thus QED

Jun 4th, 2015


Jun 4th, 2015
image.jpg

What are you trying to prove here?

Jun 4th, 2015

Do not worry I have it

Jun 4th, 2015

Do not worry I have it

Jun 4th, 2015

Do not worry I have it

Jun 4th, 2015

ok cool

Jun 4th, 2015

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