# Trigonometry math question

label Calculus
account_circle Unassigned
schedule 1 Day
account_balance_wallet \$5

Jun 4th, 2015

hi, I would love to answer your question, do you mind to type it out and post it again? Thank you

Jun 4th, 2015

Is better if you help me with this one,

(Sec x - csc x )/(sec x + csc x ) = (tan x-1/ tan x+1)

Jun 4th, 2015

so you want me to prove it right? Also is it tan(x-1) or tanx-1?

Jun 4th, 2015

Tanx-1

Jun 4th, 2015

left side:

secx-cscx=1/cosx - 1/sinx=(sinx-cosx)/(cosx*sinx)

secx+cscx=(sinx+cosx)/(cosx*sinx)

so (Sec x - csc x )/(sec x + csc x ) =(sinx-cosx)/(sinx+cosx)

right side:

(tanx-1)/(tanx+1)=(sinx/cosx - 1)/(sinx/cosx +1)=(sinx-cosx)/cosx / (sinx+cosx)/cosx=（sinx-cosx)/(sinx+cosx)

thus QED

Jun 4th, 2015

Jun 4th, 2015
image.jpg

What are you trying to prove here?

Jun 4th, 2015

Do not worry I have it

Jun 4th, 2015

Do not worry I have it

Jun 4th, 2015

Do not worry I have it

Jun 4th, 2015

ok cool

Jun 4th, 2015

...
Jun 4th, 2015
...
Jun 4th, 2015
Nov 24th, 2017
check_circle