We have to compute the integral of pi*y^2(x) dx at the given range.
Note then at this range x>0 and 7-x>0.
y^(x) = 49/(7x - x^2) = 49/[x(7-x)] = 7*(1/x + 1/(7-x)).
So V = pi*int_0.75_6_[7*(1/x + 1/(7-x)]dx = 7pi*[lnx - ln(7-x)]_0.75_6 =
7pi*ln[x/(7-x)]_0.75_6 = 7pi*(ln(6) - ln(3/25)) =
Please ask if anyting is unclear.
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