The minimum is P = at
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the feasible regions are three vertices are (0, 0), (8, 0), and (0, 8).
To find the minimum and maximum values of P,
evaluate P = 3x + 4y at each of the three vertices.
At (0, 0): P = 3(0) + 4(0) = 0 Minimum
At (8, 0): P = 3(8) + 4(0) = 24
At (0, 8): P= 3(0) + 4(8) = 32 Maximum
The minimum value of P is 0. It occurs when x = 0 and
y = 0. (0,0) The maximum value of P is 32. It occurs when
x = 0 and y = 8.
(x, y) = (0,0)
(x, y) = (0,8)
are there other possible answers for this questions?
those are the only answers
Solve the linear programming problem by the method of corners.Find the minimum and maximum of P = 4x + 2y subject to
(x, y) =
Is that the same question? The answer does not seem to be right
this question is similar like the one i have done above
It is telling me that the answer is wrong :(
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