solve the compund inequality 8x – 2 > 4 or 3x + 6 < 12

Thank you for the opportunity to help you with your question!

Solve each inequality seperatly:

8x - 2 > 4; 8x > 6; x > 6/8; x > 3/4

3x + 6 < 12; 3x < 6; x < 2

Combine two answers: 3/4 < x < 2

Hope that helps.

thank you can you help with other questions

Sure; I'll do another for you.

Solve seperatley:

10x - 4 < 6; 10x < 10; x < 1

4x - 12 < 8; 4x < 20; x < 5

In this case, since it is an "or" statement, we go with the lest restrictive: x < 5

4z + 6 >= -10; 4z >= -16; z >= -4

-3z - 5 >= -17; -3z >= -12; z <= 4

Combine: -4 <= z <= 4

Hope I have been of help. This will need to be my last problem on this topic.

For the next five problems, select the graph that fits the solution to the given absolute value equation or the given absolute value inequality.

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