### Question Description

A school is building a rectangular soccer field that has an area of 6000 square yards. The soccer field must be 40 yards longer than its width. Determine algebraically the dimensions of the soccer field, in yards.

## Final Answer

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let the width be x and length x+4

area =LW

x(x+40)=6000

x^2+40x=6000

x^2+100x-60x-6000=0

x(x+100)-60(x+100)=0

(x-60)(X+100)=0

x=60 or -100

widith=60 yards and length=100 yards

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