2y2+10y=-11

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2y²+10y=-11

2y²+10y+11=0

As a=2, b=10, c=11

By using quadratic formula, we have

y=[-(10)± √(10)²-4(2)(11)] /2(2)

y= [-10 ± √12] / 4

y = [-10+√12]/4 ; y= [-10-√12]/4

y = -10/4+2√3/4 ; y = -10/4-2√3/4

y = -5/2 + √3/2 ; y = -5/2 - √3/2

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