Need help with this quadratic eq. Can you show me how its done in fractions

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2y2+10y=-11

Jun 5th, 2015

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Jun 5th, 2015

2y²+10y=-11

2y²+10y+11=0

As a=2, b=10, c=11

By using quadratic formula, we have


y=[-(10)± √(10)²-4(2)(11)] /2(2)

y= [-10 ± √12] / 4

y = [-10+√12]/4 ;     y= [-10-√12]/4

y = -10/4+2√3/4 ;    y = -10/4-2√3/4 

y = -5/2 + √3/2  ;     y = -5/2 - √3/2  

Jun 5th, 2015

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Jun 5th, 2015
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