The pOH of an aqueous solution of 0.581 M nitrous acid is

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Onaxf2

Science

Question Description

The pOH of an aqueous solution of 0.581 M nitrous acid is 

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Explanation & Answer

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I have found that Ka for KNO2 is 7.1 x 10^-4
Check this value
HNO2 <=> H+ + NO2-
start
0.581
change
-x .. . . . .. .+x. . +x
at equilibrium
0.581-x .. . x. . . .x

Ka = (x)^2/ 0.581-x
x = [H+]= 0.0192 M
pH = - log 0.0192=1.72
pOH = 14 - pH = 14 - 1.72=12.28 ( 12.3 at 3 significant figures)


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New York University

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