Calculate the percent ionization of a 0.341 M solution of acetic acid.

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Step 1

Acetic acid HC_{2}H_{3}O_{2 molar mass}

Calculate the [H^{+}]:

[H^{+}] = √ (K_{a} times concentration)

[H^{+}] = √(1.77 x 10¯^{5} times 0.431) = 0.0776897M

Step 2)

Divide the [H^{+}] by the concentration, then multiply by 100:

(0.00133 /0.431) x 100 = 22.78%

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