equation of line that is perpendicular to another line

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Find the equation of the line, expressed in slope intercept form, that passes through (3,-2) and perpendicular to y= -2/3 X + 1

Jun 6th, 2015

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Jun 6th, 2015

The slope of:
y= -2/3x +5 
is -2/3
.
A line perpendicular must have a slope that is the negative reciprocal:
(-2/3)m = -1

(2/3)m = 1
m = 3/2 (slope of new line)
use this along with the given point (3,-2) and plug into the "point-slope" form:
y - y1 = m(x - x1)
y +2 = 3/2(x - 3)
y +2 = 3/2x - 9/2
y = 3/2x - 5/2 (this is what they're looking for -- in "slope-intercept" form) 

Jun 6th, 2015

I just checked something and need clarification. when I simplified terms y+2=3/2x -9/2, shouldn't the answer be y= 3/2x -9/2 -4/2 , which equals the an answer of y=3/2x -13/2 instead of y = 3/2 x - 5/2.  

Jun 6th, 2015

Dear thanks for correcting me. It was a problem with calculation

Jun 6th, 2015

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Jun 6th, 2015
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Jun 6th, 2015
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