# word problem question

User Generated

zanthvyne10

Mathematics

### Question Description

The owner of a
5000-gal
oil truck loads the truck with gasoline and kerosene. The profit on each gallon of gasoline is
15¢
and on each gallon of kerosene it is
14¢.
How many gallons of each fuel did the owner load if the profit was
\$725?

Student has agreed that all tutoring, explanations, and answers provided by the tutor will be used to help in the learning process and in accordance with Studypool's honor code & terms of service.

Let x be the number of gasoline and y be the number of gallons of kerosene loaded in the truck.

x+ y =5000.   Equation 1.

Profit from x gallons of gasoline= \$0.15x

Profit from y gallons of kerosene= \$0.14y

So

0.15x + 0.14y = 725.  Equation 2

Multiplying equation 1 by 0.15 and substact eq. 2 from it we get

0.15y - 0.14y = 5000x0.15 - 725

0.01y = 25

y = 25/0.01

y = 2500

Therefore y= 2500 gallons kerosene

Substituting in eq 1, we get

x= 5000- 2500 = 2500 gallons gasoline.

PurzZnguGhgbe (755)
UCLA
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Review

Anonymous
I was struggling with this subject, and this helped me a ton!

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