word problem question

Algebra
Tutor: None Selected Time limit: 1 Day

The owner of a
5000-gal 
oil truck loads the truck with gasoline and kerosene. The profit on each gallon of gasoline is
15¢ 
and on each gallon of kerosene it is
14¢. 
How many gallons of each fuel did the owner load if the profit was
$725?
Jun 7th, 2015

Thank you for the opportunity to help you with your question!

Let x be the number of gasoline and y be the number of gallons of kerosene loaded in the truck.

x+ y =5000.   Equation 1.

Profit from x gallons of gasoline= $0.15x

Profit from y gallons of kerosene= $0.14y

So

0.15x + 0.14y = 725.  Equation 2

Multiplying equation 1 by 0.15 and substact eq. 2 from it we get

0.15y - 0.14y = 5000x0.15 - 725

0.01y = 25

y = 25/0.01

y = 2500

Therefore y= 2500 gallons kerosene

Substituting in eq 1, we get

x= 5000- 2500 = 2500 gallons gasoline.



Please let me know if you need any clarification. I'm always happy to answer your questions.
Jun 7th, 2015

thank you

Jun 7th, 2015

U r welcome.

Jun 7th, 2015

Did you know? You can earn $20 for every friend you invite to Studypool!
Click here to
Refer a Friend
...
Jun 7th, 2015
...
Jun 7th, 2015
Dec 7th, 2016
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer