### Question Description

An astronaut stands by the rim of a crater on the moon, where the acceleration of gravity is 1.62 m/s2 . To determine the depth of the crater, she drops a rock and measures the time it takes for it to hit the bottom. If the depth of the crater is 120 m, how long does it take for the rock to fall?

## Explanation & Answer

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s= ut+ 0.5 a (t)^2

where s= dist traveled

u=initial velocity which is zero in this case

t= time taken to travel 's' distance

a=acceleration (due to gravity on moon i.e 1.62 m/s^2 )

120=0+0.5*1.62*t^2

148.148=t^2

t=12.17 seconds