An astronaut stands by the rim of a crater on the moon, where the acceleration of gravity is 1.62 m/s2
. To
determine the depth of the crater, she drops a rock and measures the time it takes for it to hit the bottom. If the depth
of the crater is 120 m, how long does it take for the rock to fall?

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Thank you for the opportunity to help you with your question!

s= ut+ 0.5 a (t)^2

where s= dist traveled
u=initial velocity which is zero in this case
t= time taken to travel 's' distance
a=acceleration (due to gravity on moon i.e 1.62 m/s^2 )

120=0+0.5*1.62*t^2

148.148=t^2

t=12.17 seconds

Please let me know if you need any clarification. I'm always happy to answer your questions.Please let me know if you need any clarification. I'm always happy to answer your questions.

Jun 7th, 2015

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