A 67.0-kg person throws a 0.0470-kg snowball forward with a ground speed of 32.0

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Science

Question Description

67.0-kg person throws a 0.0470-kg snowball forward with a ground speed of 32.0 m/s. A second person, with a mass of 56.0 kg, catches the snowball. Both people are on skates. The first person is initially moving forward with a speed of 2.00 m/s, and the second person is initially at rest. What are the velocities of the two people after the snowball is exchanged? Disregard the friction between the skates and the ice.

thrower     m/s
catcher     m/s

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Explanation & Answer

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mass of the first person=67

mass of snowball 0.0470 velocity 32m/s

mass of second person=56 velocity of first person=2m/s

let the velocity of the first person be x

67x=0.047 x 32

x=1.504/67

=0.0224m/s

v(67-56)=2 x 67

11v=134

v=12.18m/s


 

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athalnt (125)
Purdue University

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