Two chords of a circle intersect. The point of intersection divides the first chord into two
segments of length 5 cm and 8 cm and divides the second chord into two segments, one
which has length 4 cm. How long is the second chord?
When two chords intersect each other inside a circle, the products of their segments are equal.
Let the length of unknown segment of the second chord be x.
5*8 = 4*x
40 = 4x
4x = 40
x = 40/4
x = 10 cm
Length of the second chord = 4 + x = 4 + 10 = 14 cm
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