Mathematics
Slope Intercept Equation

Question Description

Write an equation for the line in point slope form and general form

Passing through (6, -9) and perpendicular to the line whose equation is x-8y-3=0

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Final Answer

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1.Find the  gradient of the line

for perpendicular lines G1 x G2 = -1

x - 8y -3 = 0

-8y = - x + 3

y = 1/8 x -3

G1 = 1/8

1/8 G2 = -1

G2 = - 8

The "point-slope" form of the equation of a straight line is:

y - y1 = m(x - x1)

The coordinates are

(6, -9)

 so (y - -9) = -8(x-6)

=( y + 9) = -8(x - 6)

I am submitting the general form in my next submission due to time.

Please let me know if you need any clarification. I'm always happy to answer your questions.

Mayweather (69)
Rice University

Anonymous
This is great! Exactly what I wanted.

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