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1.Find the gradient of the line
for perpendicular lines G1 x G2 = -1
x - 8y -3 = 0
-8y = - x + 3
y = 1/8 x -3
G1 = 1/8
1/8 G2 = -1
G2 = - 8
The "point-slope" form of the equation of a straight line is:
y - y1 = m(x - x1)
The coordinates are
so (y - -9) = -8(x-6)
=( y + 9) = -8(x - 6)
I am submitting the general form in my next submission due to time.
Please let me know if you need any clarification. I'm always happy to answer your questions.
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