Can somebody please help me with my physics homework

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A car moves from the point (3.0 m) xˆ + (5.0 m) yˆ to the point (8.0 m) xˆ - (7.0 m) yˆ in 2.0 s. What is the

direction of the average velocity of the car?

Jun 7th, 2015

Thank you for the opportunity to help you with your question!

Average velocity= distance/time

Average velocity=[ (8.0 m) xˆ - (7.0 m) yˆ] - [(3.0  m) xˆ + (5.0 m) yˆ]/2

Average velocity= [ (5 m) xˆ- (12 m) yˆ]/2

Average velocity= [ (2.5 m) xˆ- (6 m) yˆ]


Please let me know if you need any clarification. I'm always happy to answer your questions.
Jun 7th, 2015

what is the final answer?

Jun 7th, 2015

Average velocity= [ (2.5 m) xˆ- (6 m) yˆ]
`this is the final answer with direction of average velocity 2.5 meter on x axis and -6 meter on y axis

please select my bids i will provide u A+ answers 

Jun 7th, 2015

according to the question the answer should be  - 67 degrees  from the x-axis

Jun 7th, 2015

This answer that you provide me is wrong :/

Jun 7th, 2015

what ???
is the question u mention was right ?
because accourding to question this is the right answer.... 

Jun 7th, 2015

A car moves from the point (3.0 m) xˆ + (5.0 m) yˆ to the point (8.0 m) xˆ - (7.0 m) yˆ in 2.0 s. What is the

direction of the average velocity of the car?

A) 67° from the x-axis

B) -67° from the x-axis

C) 33° from the x-axis

D) -33° from the x-axis

Answer: B

This is the question


Jun 7th, 2015

direction is = tan(y/x)

direction is = tan(6/2.5)

direction is = 67 degree

please add this in the above answer which i gave....
this was missing in the answer
i thought that was enough sorry that was due to misunderstanding

Jun 7th, 2015

No is great thanks a lot :)

Jun 7th, 2015

welcome dear sorry for the misunderstanding :)

Jun 7th, 2015

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