A car moving at 10.0 m/s encounters a bump that has a circular cross-section with a radius of 30.0 m. What is
the normal force exerted by the seat of the car on a 60.0-kg passenger when the car is at the top of the bump?

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The forces acting on the car at the highest point of the bump are its weight downward and normal force up. There has to be a net force downward force to keep the car moving over the bump.

mass = 60 kg speed = 10 m/s force by the seat = Fseat

mv^2/R = N - mg N = m(g + v^2/R) = (60)(9.8 + (10)^2/30)

Answer=788 N

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