Description
A satellite has a mass of 94 kg and is located at 1.96 106 m above the surface of Earth.
(a) What is the potential energy associated with the satellite at this location? (b) What is the magnitude of the gravitational force on the satellite?
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Explanation & Answer
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b) The acceleration due to gravity at sea level is:
g = G M/R²
R = Earth's radius
At h = 1.96 10^6 m of altitude:
g' = G M/(R+h)²
By dividing the equations:
g'/g = R²/(R+h)²
g' = g R²/(R+h)²
F = m g' = m g R²/(R+h)² = 94 * 9.8 * 6371000²/(6371000 + 1.97 10^6)²
F = 55501.575 N
= = = = = = =
a) U = m g' (R + h) – m g R = m g R²/(R+h) – m g R
U = m g R (R/(R+h) – 1) = - m g R h/(R+h)
U = - 94 * 9.8 * 6371000 * 1.96 10^6/(6371000 + 1.96 10^6)
U = -442,871.24 J
= = = = = = = = = =
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