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t=0s then at t=1 you're going 0.410m/s then at 2s its 0.82m/s and so on
We can find the distance travelled by using constant acceleration equation:
wf^2 = wi^2 + 2angular acceleration*(theta - theta initial) wf and wi are angular speeds final and initial respectively. theta and theta initial are angular displacement final and initial respectively.
Since x = r*theta, v = r*w, a = r*(angular acceleration)
w = v/r = 10.7145/284 = .037727 rad/s
ang acceler = 037727/284 = 1.32x10^-4 rad/s^2
Using the equation above:
037727^2 = 0^2 + 2*1.32x10^-4*theta
5.357 = theta
x = r*theta, so the distance travelled is
x =r* theta = 284m * 5.35 = 1521 m
b) the car has travelled 1521 m when the speed is 10.7145 m/s
c) time elapsed:
theta = theta0 + wt + .5angular acceleration * t^2
theta = .5at^2, since angular speed is zero initially and angular displacement is zero.
root(2theta/a) = t
t = root(2*5.35/1.32x10^-4) = 810.6 seconds
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