A 67.0-kg person throws a 0.0470-kg snowball forward with a ground speed of 32.0

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zwbbql132

Science

Question Description

67.0-kg person throws a 0.0470-kg snowball forward with a ground speed of 32.0 m/s. A second person, with a mass of 56.0 kg, catches the snowball. Both people are on skates. The first person is initially moving forward with a speed of 2.00 m/s, and the second person is initially at rest. What are the velocities of the two people after the snowball is exchanged? Disregard the friction between the skates and the ice.

thrower     m/s
catcher     m/s

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Explanation & Answer

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we can apply force momentum equation as fallows

to snow ball and 2nd person

0.047*32=(56+0.047)*v

v=0.047*32/56.047

v=0.026 m/s

so the catcher speed 0.026 m/s 

applying force momentum for ball and first person

67*2-0.047*32=67*u

u=67*2-0.047*32/67

u=1.98 m/s

so the thrower speed=1.98 m/s


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fnpuvagun (127)
UCLA

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