A satellite has a mass of 94 kg and is located at 1.96 106 m above the surface of Earth.

(a) What is the potential energy associated with the satellite at this location?

(b) What is the magnitude of the gravitational force on the satellite?

a) U = m g' (R + h) – m g R = m g R²/(R+h) – m g R U = m g R (R/(R+h) – 1) = - m g R h/(R+h) U = - 94 * 9.8 * 6371000 * 1.97 10^6/(6371000 + 1.97 10^6) U = 1386148117.01 J

= - 1386.15 * 10^6 J

b) The acceleration due to gravity at sea level is: g = G M/R² R = Earth's radius At h = 1.96 *10^6 m of altitude: g' = G M/(R+h)² By dividing the equations: g'/g = R²/(R+h)² g' = g R²/(R+h)² F = m g' = m g R²/(R+h)² = 94 * 9.8 * 6371000²/(6371000 + 1.97*10^6)² F = 537.44 N

the first one is not correct

Try that in different forms

I am sorry....

-1380767229.86

= - 1380.77 * 10^6 J

still gave me incorrect

Try that in different forms............................................................................................................................................

i've tried is incorrect

I double checked the answer. its correct

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