A race car starts from rest on a circular track of radius 578 m. The car's speed

label Physics
account_circle Unassigned
schedule 1 Day
account_balance_wallet $5

A race car starts from rest on a circular track of radius 578 m. The car's speed increases at the constant rate of 0.740 m/s2. At the point where the magnitudes of the centripetal and tangential accelerations are equal, find the following. 

(a) the speed of the race car 

(b) the distance traveled 

( c) the elapsed time 
Jun 8th, 2015

Thank you for the opportunity to help you with your question!

Centri. accl = v^2/r = 0.74

solving we get    (a)   velocity of car  = 20.68 m/sec

(C) v = u+at ; 20.68 = 0.74 t or we get   time = 27.94 sec   or 28 sec

B)   distance traveled = S = 0.5 * 0.74 * 27.94^2  = 288.84 m

A: 20.68 m/s

B : 288.84 m

C : 28 sec

You can use my promo code: Saroj N , while signing up at study pool and enjoy $10 absolutely free….

Please find the solution enclosed here with .. In case of any doubt please feel free to ask… Do not forget to best my answer… If you are having some other problem please feel free to contact me for quick & quality services..
Jun 8th, 2015

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
Jun 8th, 2015
Jun 8th, 2015
Oct 21st, 2017
Mark as Final Answer
Unmark as Final Answer
Final Answer

Secure Information

Content will be erased after question is completed.

Final Answer