A race car starts from rest on a circular track of radius 578 m. The car's speed increases at the constant rate of 0.740 m/s2. At the point where the magnitudes of the centripetal and tangential accelerations are equal, find the following.
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Centri. accl = v^2/r = 0.74
solving we get (a) velocity of car = 20.68 m/sec
(C) v = u+at ; 20.68 = 0.74 t or we get time = 27.94 sec or 28 sec
B) distance traveled = S = 0.5 * 0.74 * 27.94^2 = 288.84 m
A: 20.68 m/s
B : 288.84 m
C : 28 sec
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