A race car starts from rest on a circular track of radius 578 m. The car's speed increases at the constant rate of 0.740 m/s2. At the point where the magnitudes of the centripetal and tangential accelerations are equal, find the following.
Thank you for the opportunity to help you with your question!
Centri. accl = v^2/r = 0.74
solving we get (a) velocity of car = 20.68 m/sec
(C) v = u+at ; 20.68 = 0.74 t or we get time = 27.94 sec or 28 sec
B) distance traveled = S = 0.5 * 0.74 * 27.94^2 = 288.84 m
A: 20.68 m/s
B : 288.84 m
C : 28 sec
You can use my
promo code: Saroj N , while signing up at study pool and enjoy $10
Please find the solution enclosed here with .. In case of any doubt please feel free to ask… Do not forget to best my answer… If you are having some other problem please feel free to contact me for quick & quality services..
Jun 8th, 2015
Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.