Science
A dentist's drill starts from rest. After 2.60 s of constant angular acceleratio
Question Description
A dentist's drill starts from rest. After 2.60 s of constant angular acceleration it turns at a rate of
(a) Find the drill's angular acceleration.
rad/s2
(b) Determine the angle (in radians) through which the drill rotates during this period.
rad
rad/s2
(b) Determine the angle (in radians) through which the drill rotates during this period.
rad
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Final Answer
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DATA:
T= 2.60s
Angular speed= 2.7*104 rev/min = 1.62*106 rev/s
Angular acceleration=?
Angle=?
SOLUTION:
Angular acceleration= angular speed/time
= 1.62*106/2.60
= 6.2307*105rad/s
Angular speed= angle/time
Angle = angular speed*time
= 1.62*106*2.60
= 4.2120*106
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Ahsan N.
(560)
New York University
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