A dentist's drill starts from rest. After 2.60 s of constant angular acceleratio

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A dentist's drill starts from rest. After 2.60 s of constant angular acceleration it turns at a rate of 2.7  104 rev/min.

(a) Find the drill's angular acceleration.

(b) Determine the angle (in radians) through which the drill rotates during this period.
Jun 8th, 2015

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T= 2.60s

Angular speed= 2.7*104 rev/min = 1.62*106 rev/s

Angular acceleration=?



Angular acceleration= angular speed/time

  = 1.62*106/2.60

  = 6.2307*105rad/s

Angular speed= angle/time

Angle = angular speed*time

  = 1.62*106*2.60

  = 4.2120*106

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Jun 8th, 2015

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