A dentist's drill starts from rest. After 2.60 s of constant angular acceleratio

label Physics
account_circle Unassigned
schedule 1 Day
account_balance_wallet $5

A dentist's drill starts from rest. After 2.60 s of constant angular acceleration it turns at a rate of 2.7  104 rev/min.

(a) Find the drill's angular acceleration.

(b) Determine the angle (in radians) through which the drill rotates during this period.
Jun 8th, 2015

Thank you for the opportunity to help you with your question!


T= 2.60s

Angular speed= 2.7*104 rev/min = 1.62*106 rev/s

Angular acceleration=?



Angular acceleration= angular speed/time

  = 1.62*106/2.60

  = 6.2307*105rad/s

Angular speed= angle/time

Angle = angular speed*time

  = 1.62*106*2.60

  = 4.2120*106

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jun 8th, 2015

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
Jun 8th, 2015
Jun 8th, 2015
Jun 25th, 2017
Mark as Final Answer
Unmark as Final Answer
Final Answer

Secure Information

Content will be erased after question is completed.

Final Answer