A man jogs at a speed of 1.1 m/s. His dog waits 2.1 s and then takes oﬀ running at a speed of 2.2 m/s to catch the man. How far will they have each traveled when the dog catches up with the man? Answer in units of m.
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Let the man got caught after t second....
distance traveled by man in t sec = Speed * time = 1.1 *t m
distance traveled by dog in (t-2.1) sec = Speed * time = 2.2*(t-2.1) m
the moment when dog caught man : Distance traveled by both will be same hence
1.1t = 2.2 (t-2.1)
or 1.1t = 2.2t -4.62
1.1t = 4.62 ot t = 4.2 sec
Hence distance = 1.1*4.2 = 4.62 m (Answer)
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Jun 8th, 2015
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