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Physics
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A man jogs at a speed of 1.1 m/s. His dog waits 2.1 s and then takes off running at a speed of 2.2 m/s to catch the man. How far will they have each traveled when the dog catches up with the man?
Answer in units of m.

Jun 8th, 2015

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Let the man got caught after  t second....

distance traveled by man in t sec = Speed * time = 1.1 *t   m

distance traveled by dog in (t-2.1) sec = Speed * time = 2.2*(t-2.1)    m

the moment when dog caught man  : Distance traveled by both will be same hence

1.1t = 2.2 (t-2.1)

or 1.1t = 2.2t -4.62

1.1t = 4.62    ot t = 4.2 sec

Hence distance = 1.1*4.2 =   4.62 m (Answer)

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Jun 8th, 2015

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