The acceleration when moving by circle at uniform speed is v^2/r where v is the speed and r is the radius. The direction of acceleration it from the current position towards the center.
Here r = (228*4)/(2pi) approx.= 145.15 (m), v = 228/35 approx= 6.51 (m/s) (as in your answer).
So a = v^2/r approx.= 0.29 (m/s^2).
Now express the direction af acceleration at the point B "counterclockwise the +x-axis". For that, continue the line BO to the upper-left (to some point, denote it B'). Then the angle in question will be COB' and it is clearly counterclockwise (in standard position) and is equal to (180-35) = 145 degrees.
Please ask if anything is unclear.
Jun 8th, 2015
Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.