Gen Physics I HmWk 1 Serway 10 Ed (Homework)

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A 4.0-g bullet leaves the muzzle of a rifle with a speed of 328 m/s. What force (assumed constant) is exerted on the bullet while it is traveling down the 0.80-m-long barrel of the rifle?

Jun 8th, 2015

Thank you for the opportunity to help you with your question!

The bullet starts from rest.

original velocity = 0
final velocity = 328
displacement= .80
acceleration= ?

final velocity^2 = original velocity^2 + (2)(acceleration)(displacement)

  107584= 1.6acceleration

acceleration = 67240

force = (mass)(acceleration)

The mass is 4g to make the units consistent we will convert to kg.

The mass is .004 kg

force = (.004)(67240) = 268.96 N

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jun 8th, 2015

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