The concentration of carbon monoxide in an urban apartment is 49 µg/m3.

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Science

Question Description

The concentration of carbon monoxide in an urban apartment is 49 µg/m3. What mass of carbon monoxide in grams is present in a room measuring 8 ✕ 12 ✕ 22 ft? (Enter your answer to three digits.) Explain

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Explanation & Answer

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Step 1 
Find the volume in Cubic Feet. 

V = l*w*h 
V = 8 * 12 * 22 
V = 2112 cu feet. 

Step 2 
Convert this to cubic meters 
Conversion Factor 1 m^3 = 35.315 ft^3 
1 m^3 = 35.315 ft^3 
x = 2112 ft^3 

x = 2112/35.315 
x = 59.80 m^3 

Step 3 
Find the Carbon Monoxide. 

1 m^3 = 43 micrograms Carbon Monoxide. 
59.80 m^3 = x 

x = 2571.60 micrograms. 

Step 4 
Convert Micrograms into grams. 

1 gram = 1*10^6 micrograms. 
x gram = 2571.60 micrograms. 

x = 2.5716 * 10^-3 grams.

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