solve by substitution :
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1/5z+1/2u=1/10 (1) and 1/5z+3u=13/5 (2)
From (1) we can write that 1/5z=1/10-1/2u
We substitute in (2) 1/10-1/2u+3u=13/5 <=>5/2u=13/5-1/10 <=> 5/2u=5/2 <=> u=1
Then using for example (1) 1/5z+1/2=1/10 <=> 1/5z=-4/10 <=> z=-2
Hope it helps !!!
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