anyone call for a substitution

Algebra
Tutor: None Selected Time limit: 1 Day

solve by substitution :

 1/5z+1/2u=1/10

1/5z+3u=13/5

Jun 8th, 2015

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1/5z+1/2u=1/10 (1) and 1/5z+3u=13/5 (2)

From (1) we can write that 1/5z=1/10-1/2u

We substitute in (2) 1/10-1/2u+3u=13/5 <=>5/2u=13/5-1/10  <=> 5/2u=5/2 <=> u=1

Then using for example (1) 1/5z+1/2=1/10 <=> 1/5z=-4/10 <=> z=-2

Hope it helps !!!

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jun 8th, 2015

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