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4) if the track has 10 degree down grade

f=ma

20+5*9.8 sin 10=5*a

a=28.5/5

a=5.7 m/s^2


5)10 degree up grade

20-5*9.8*sin 10=5* a

5a=20-8.5

a=11.5/5

a=2.3 m/s^2

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sachintha (127)
UC Berkeley

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