##### Math Question pre cal 11

 Calculus Tutor: None Selected Time limit: 1 Day

Remainder: Find the smallest integer which will give a remainder of 1 when divided by 2, 3, 4, 5, 6, 7, 8, or 9

Jun 9th, 2015

LCM for 2= 3

4 = 9

5 = 26

6 = 37

7 = 50

8 = 65

9 =82

Jun 9th, 2015

Can you explain how you got you answer:?

Jun 9th, 2015

Yes! So we want to figure out the smallest number that can be divided by the answer.

So, starting with x/2. 2/2 would = 1. So we make it x+1 for the answer. so if x=2 then x+1 would = 3

I apologize about number "4". Let me redo that.. so x/4= 1 so x =4 so x+1 = 5

So, if we apply this to everything then

2: ans=3

3: ans=4

4 ans = 5

5 ans = 6

6 ans = 7

8 ans = 9

9 ans = 10

I apologize again. I was finding the least common multiple at first. BUT this is how to find the least common integer. So sorry again for the confusion! Again, my apologies. I'm happy to answer anything else in more detail. But please disregard first.

Jun 9th, 2015

And by least common = smallest (i/e: minimal)

Jun 9th, 2015

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Jun 9th, 2015
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Jun 9th, 2015
Dec 8th, 2016
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