Mathematics
need to find the following function

Question Description

for g(x)=x^2+2x+2, what is the function' s minimum or maximum value?

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Final Answer

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g(x)  = x^2+2x+2

g'(x) = 2x+2 =0 hence x = -1

g''(x) = 2  (which is >0 for x=-1 hence at x = -1 function will have minimum value )

Minimum value g(-1) = (-1)^2+2*(-1)+2 = 1-2+2 =1

hence Minimum value = 1   & maximum value = Infinity


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