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for g(x)=x^2+2x+2, what is the function' s minimum or maximum value?
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Explanation & Answer
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g(x) = x^2+2x+2
g'(x) = 2x+2 =0 hence x = -1
g''(x) = 2 (which is >0 for x=-1 hence at x = -1 function will have minimum value )
Minimum value g(-1) = (-1)^2+2*(-1)+2 = 1-2+2 =1
hence Minimum value = 1 & maximum value = Infinity
zngurkcreg121
(697)
UIUC
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