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Balanced Reaction :
2NaOH + 2Al + 6H2O ---> 2NaAl(OH)4 + 3H2
Same as above ,
V = Moles * Constant
4 = n * 22,4
n = 4/22,4 = 0.1786
Moles of Aluminium / Moles of Hidrogen = Coefficient of Aluminium / Coefficient of Hidrogen
n / 0.1786 = 2 / 3
n = 0.119 Mole
M = n*Mr = 0.119* 27 = 3,213 grams
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