Description
Q3:
In the combustion reaction of 149g of propane(C3H8) with excess oxygen, what volume of carbon dioxide(CO2) is produced at STP?
(note: balance the reaction first)
C3H8 + O2 3CO2 + H2O
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Explanation & Answer
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molecular wt of C3H8=12*3+1*8
=36+6
=42
MOLES OF C3H6=149/42
=3.5476
moles of co2
=3.5476*3
10.6428=v/44
=44*10.6428
468.2832ml of CO2
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