Chemistry Homework Help

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Question Description

Q3:

In the combustion reaction of 149g of propane(C3H8) with excess oxygen, what volume of carbon dioxide(CO2) is produced at STP?

(note: balance the reaction first)

C3H8  +   O2     3CO2  +  H2O

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Explanation & Answer

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molecular wt of C3H8=12*3+1*8

=36+6

=42

MOLES OF C3H6=149/42

=3.5476

moles of co2

=3.5476*3

10.6428=v/44

=44*10.6428

468.2832ml of CO2

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NXBAAPUNZOREYNVA (196)
New York University

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