Chemistry Homework Help

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Q3:

In the combustion reaction of 149g of propane(C3H8) with excess oxygen, what volume of carbon dioxide(CO2) is produced at STP?

(note: balance the reaction first)

C3H8  +   O2     3CO2  +  H2O

Jun 9th, 2015

Thank you for the opportunity to help you with your question!

The balanced reaction is:

C3H8  +   5O2     3CO2  +  4H2O

Number of moles of propane is 149g/44g/mole = 3.386 moles

Ratio of moles C3H8:CO2 is 1:3.

So we can use the proportion: 1/3=3.386/x, where x is a number of moles of CO2.

x = 3.386*3 = 10.158 moles of CO2

Volume of CO2 is 10.158 moles*22.4L = 227.54L

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jun 9th, 2015

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