Find the net torque on the wheel in the figure below about the axle through O pe

label Physics
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Jun 10th, 2015

Thank you for the opportunity to help you with your question!

The angle θ = 25.9º is an irrelevant distraction. Like F1 and F2, F3 is directed tangentially (perpendicular to the displacement vector) at the point of contact. So you would use a 90º angle. 


Torque: τ = r × F 

F3 may be directed 25.9º counterclockwise from left but r3 is directed 25.9º counterclockwise from up. The difference in direction is 90º. 



Clockwise torque: 

τ = ( F1 + F2 )( b ) - ( F3 )( a ) 
τ = ( 10.7N + 8.55N )( 0.25m ) - ( 12.9N )( 0.9m  
τ = 6.79 Nm

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jun 10th, 2015

wrong answer


Jun 10th, 2015

wrong answer


Jun 10th, 2015

wrong answer


Jun 10th, 2015

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