In the morning, maria drove to a business appointment at 60mph. Her average speed on the return trip in the afternoon was 50 mph. the return trip took 1/5hr longer because of heavy traffic. How far did she travel to the appointment?
Thank you for the opportunity to help you with your question!
Let x = time of travel to appointment
then, x + 1/5 = time of return trip
Distance going = 60x
Distance returning = 50(x+1/5)
Distance going = Distance returning
60x = 50(x+1/5)
60x = 50x + 10
10x = 10
x = 1 hour
therefore, distance traveled to appoint is
60(1) = 60 miles
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