Distance equation, I need help.

label Algebra
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schedule 1 Day
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In the morning, maria drove to a business appointment at 60mph. Her average speed on the return trip in the afternoon was 50 mph. the return trip took 1/5hr longer because of heavy traffic. How far did she travel to the appointment?

Jun 10th, 2015

Thank you for the opportunity to help you with your question!

Let x = time of travel to appointment

then, x + 1/5 = time of return trip

Distance going = 60x

Distance returning = 50(x+1/5)

Distance going = Distance returning

therefore,

60x = 50(x+1/5)

60x = 50x + 10

10x = 10

x = 1 hour

therefore, distance traveled to appoint is

60(1) = 60 miles

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jun 10th, 2015

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Jun 10th, 2015
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Jun 10th, 2015
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