Four objects are held in position at the corners of a rectangle by light rods as shown in the figure below. (The mass values are given in the table.)
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moment of inertia =Sum[ mass x distance^2] where the distance is the distance from the chosen rotation axis a) here, moment of inertia = (2.7+2.1+4.5+2.3)3^2 = 104.4kgm^2 because each mass is 3 m from the x axis b) now we consider distances from the y axis; each mass is 2m from the y axis: I=(2.7+2.1+4.5+2.3)2^2=46.4 kgm^2 c) the distance from the rotation axis is now found from the pythagorean theorem distance^2=2^2+3^2=13 I=(2.7+2.1+4.5+2.3)*13=150.8 kgm^2
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