Thank you for the opportunity to help you with your question!

ill chose group 1

y=-3/2x+4 so the slope is -3/2 and the intercept is 4 since at x=0 y=4

I would first find the y-int on the graph and make a point there. Then i would find what y is at x=1 which is easy since it is 4-3/2. Then I would draw a line through the 2 points and expand it since the slope never changes which means that after the two points the line should be increasing at the same rate.

-3x+2y=8

2y=3x+8

y=3/2x+4 the slope is 3/2 and the y-int is 4

Similar to above I would first find the y-int on the graph and make a point there. Then i would find what y is at x=1 which is easy since it is 4+3/2. Then I would draw a line through the 2 points and expand it since the slope never changes which means that after the two points the line should be increasing at the same rate.

They are the same as they have the same slopes 3/2 howeveer are different since one is increasing at a rate of 3/2 while the other is decreasing at a rate of 3/2. Their y-ints are the same but for the first equation the graph goes from top left to bottom right while the second graph goes from the bottom left to the top right. The 2 graphs make an x

Please let me know if you need any clarification. I'm always happy to answer your questions.