Thank you for the opportunity to help you with your question!
The only method I know is to assume that you have a 100 gram sample, so you have:
14.3g H, and 85.7gC
convert these to moles
14.3g H (1 mol H/1.01g H) = 14.16
85.7g C (1 mol C/12.01g C) = 7.135
To find the ratio between atoms, divide all of your components (in this case you only have two) by the lowest number of moles. So
14.16/7.135 =~ 2
7.135/7.135 = 1
Now you know your empirical formula is CH2. You know that the molar mass is 42.00g, so divide this by the molecular weight of CH2
42/14.03 =~ 3
Since you know how many times larger the molecular formula is than the empirical, you can multiply your empirical number by three to get the molecular formula, C3H6
Please let me know if you nea case for torture by michale levined any clarification. I'm always happy to answer your questions.
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